If x + y = 6, y + z = 4 and z + x = 2, then 2y - z - x?
Created: 6 years ago |
Updated: 11 months ago
best des
Let's solve the given system of equations:
x + y = 6 ---(1)
y + z = 4 ---(2)
z + x = 2 ---(3)
We can solve this system by adding equations (1) and (3) to eliminate x:
(x + y) + (z + x) = 6 + 2
2x + y + z = 8
Now, we have two equations:
2x + y + z = 8 ---(4)
y + z = 4 ---(5)
Let's subtract equation (5) from equation (4) to eliminate y and z:
(2x + y + z) - (y + z) = 8 - 4
2x = 4
x = 2
Substitute the value of x into equation (1):
2 + y = 6
y = 4
Substitute the values of x and y into equation (2):
4 + z = 4
z = 0
Now, we have x = 2, y = 4, and z = 0. Let's calculate 2y - z - x:
2y - z - x = 2(4) - 0 - 2
= 8 - 2
= 6
Therefore, 2y - z - x is equal to 6.
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